ABOUT HCl
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- Posts:190
- Joined:Sat Apr 23, 2011 8:55 am
- Location:Khulna
Let, we have taken $ 10^{-9} $ M HCl. now, $ pH=-(log [H^{+}]).=-(log 10^{-9})=-(-9)log 10=9 $ . & We know that pH greater than 7 are base. but, HCl is acid ?? so, what is the problem ??
Re: ABOUT HCl
Remember that in an aquas solution you already have $[H^+]=10^{-7}$. You can't make it less than that.
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